Tahukah Kalian?: April 2013

Kali ini saya akan menjelaskan tentang Subneting IP Addres Kelas C,seperti yang telah kita ketahui pada Kelas C terdapat 3 Oktet sebagai Network dan 1 Oktet sebagai Host. Untuk lebih mudah dalam mengingat Pembagian Subnetmask pada kelas C perhatikan Tabel baerikut:

Subnet Mask Yang Bisa Digunakan Untuk Kelas C

Subnet Mask	Nilai CIDR
255.255.255.128	/25
255.255.255.192	/26
255.255.255.224	/27
255.255.255.240	/28
255.255.255.248	/29
255.255.255.252	/30

Dan yang perlu diingat dalam Subnet kali ini adalah:

10000000 = 128 (/25)

11000000 = 192 (/26)

11100000 = 224 (/27)

11110000 = 240 (/28)

11111000 = 248 (/29)

11111100 = 252 (/30)

11111110 = 254 (/31)

11111111 = 255 (/32)

2¹= 2 2¹¹ = 2048 2²¹ = 2097152

2²= 4 2¹²= 4096 2²² = 4194304

2³ = 8 2¹³ = 8192 2²³= 8388608

2⁴ = 16 2¹⁴= 16384

2⁵ = 32 2¹⁵= 32768

2⁶ = 64 2¹⁶ = 65536

2⁷ = 128 2¹⁷ = 131072

2⁸ = 256 2¹⁸ = 262144

2⁹ = 512 2¹⁹= 524288

2¹⁰ = 1024 2²⁰ = 1048576

Berhubung kali ini saya menjelaskan tentang IP Addres Kelas C, saya memiliki tugas dari dosen saya berikut beberapa contoh soal untuk menentukan Subnet dan Host Valid beserta cara penyelesaiannya.

Soal:

Tentukan Subnetnya dan Tentukan Host Validnya

1. 192.168.16.0 /27

2. 192.168.16.0 /28

3. 192.168.16.0 /29

4. 192.168.16.0 /30

5. 192.168.16.0 /25

Penyelesaian:

*192.168.16.0/27

Subnet mask: 11111111.11111111.11111111.11100000 ( 255.255.255.224 )

Kelas C

1. Jumlah subnet = 2³= 8 Subnet

2. Jumlah host = 2⁵ – 2 = 30 Host

3. Blok subnet = 256 – 224 = 32 ( 0,32,64,96, 128,160,192,224 )

4. Alamat host yang valid : ((Host awal – Host Akhir))

NO	SUBNET	HOST AWAL	HOST AKHIR	BROADCAST
1.	192.168.16.0	192.168.16.1	192.168.16.30	192.168.16.31
2.	192.168.16.32	192.168.16.33	192.168.16.62	192.168.16.63
3.	192.168.16.64	192.168.16.65	192.168.16.94	192.168.16.95
4.	192.168.16.96	192.168.16.97	192.168.16.126	192.168.16.127
5.	192.168.16.128	192.168.16.129	192.168.16.158	192.168.16.159
6.	192.168.16.160	192.168.16.161	192.168.16.190	192.168.16.191
7.	192.168.16.192	192.168.16.193	192.168.16.222	192.168.16.223
8.	192.168.16.224	192.168.16.225	192.168.16.254	192.168.16.255

*192.168.16.0/28

Subnet mask: 11111111.11111111.11111111.11110000 ( 255.255.255.240 )

Kelas C

1. Jumlah subnet = 2⁴ = 16 Subnet

2. Jumlah host = 2⁴ – 2 = 14 Host

3. Blok subnet = 256 – 240 = 16
( 0,16,32,48,64,80,96,112,128,144,160,176,192,208,224,240)

4. Alamat host yang valid : ((Host Awal – Host Akhir))

NO	SUBNET	HOST AWAL	HOST AKHIR	BROADCAST
1.	192.168.16.0	192.168.16.1	192.168.16.14	192.168.16.15
2.	192.168.16.16	192.168.16.17	192.168.16.30	192.168.16.31
3.	192.168.16.32	192.168.16.31	192.168.16.46	192.168.16.47
4.	192.168.16.48	192.168.16.49	192.168.16.62	192.168.16.63
5.	192.168.16.64	192.168.16.65	192.168.16.78	192.168.16.79
6.	192.168.16.80	192.168.16.81	192.168.16.94	192.168.16.95
….	……………..	…………….	……………...	…………….
14.	192.168.16.192	192.168.16.193	192.168.16.224	192.168.16.225
15	192.168.16.224	192.168.16.225	192.168.16.238	192.168.16.239
16	192.168.16.240	192.168.16.241	192.168.16.254	192.168.16.255

*192.168.16.0/29

Subnet mask: 11111111.11111111.11111111.11111000 ( 255.255.255.248 )

Kelas C

1. Jumlah subnet = 2⁵ = 32 Subnet

2. Jumlah host = 2³ – 2 = 6 Host

3. Blok subnet = 256 – 248 = 8
( 0,8,16,24,32,40,48,56,64,72,80,88,96,104,112,120,128,136,144,

152,160,168,176,184,192,200,208,216,224,232,240,248)

4. Alamat host yang valid : ((Host Awal = Host Akhir))

NO	SUBNET	HOST AWAL	HOST AKHIR	BROADCAST
1.	192.168.16.0	192.168.16.1	192.168.16.6	192.168.16.7
2.	192.168.16.8	192.168.16.9	192.168.16.14	192.168.16.15
3.	192.168.16.16	192.168.16.17	192.168.16.22	192.168.16.23
4.	192.168.16.24	192.168.16.25	192.168.16.30	192.168.16.31
5.	192.168.16.32	192.168.16.33	192.168.16.38	192.168.16.39
6.	192.168.16.40	192.168.16.41	192.168.16.46	192.168.16.47
7.	192.168.16.48	192.168.16.49	192.168.16.54	192.168.16.55
….	………………	……………….	………………	……………..
31	192.168.16.240	192.168.16.240	192.168.16.240	192.168.16.240
32	192.168.16.248	192.168.16.248	192.168.16.248	192.168.16.248

*192.168.16.0/30

Subnet mask: 11111111.11111111.11111111.11111100 ( 255.255.255.252 )

Kelas C

1. Jumlah subnet = 2⁶ = 64 Subnet

2. Jumlah host = 2² – 2 = 2 Host

3. Blok subnet = 256 – 252 = 4 (0,4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96,100,104,108,112116,120,124,128,132,136,140,144,148,152,156,160,164,168,172,176,180,184,188,192,196,200,204, 208,212,216,220,224,228,232,236,240,244,248,252)

4. Alamat host yang valid : ((Host Awal – Host Akhir))

NO	SUBNET	HOST AWAL	HOST AKHIR	BROADCAST
1.	192.168.16.0	192.168.16.1	192.168.16.2	192.168.16.3
2.	192.168.16.4	192.168.16.5	192.168.16.6	192.168.16.7
3.	192.168.16.8	192.168.16.9	192.168.16.10	192.168.16.11
4.	192.168.16.12	192.168.16.13	192.168.16.14	192.168.16.15
5.	192.168.16.16	192.168.16.17	192.168.16.18	192.168.16.19
6.	192.168.16.20	192.168.16.21	192.168.16.22	192.168.16.23
7.	192.168.16.24	192.168.16.25	192.168.16.26	192.168.16.27
….	………………	……………….	……………..	……………..
63	192.168.16.248	192.168.16.249	192.168.16.250	192.168.16.251
64	192.168.16.252	192.168.16.253	192.168.16.254	192.168.16.255

*192.168.16.0/25

Subnet mask: 11111111.11111111.11111111.10000000 ( 255.255.255.128 )

Kelas C

1. Jumlah subnet = 2¹ = 2 Subnet

2. Jumlah host = 2⁷ – 2 = 126 Host

3. Blok subnet = 256 – 128 = 128 ( 0,128)

4. Alamat host yang valid : ((Host awal – Host Akhir))

NO	SUBNET	HOST AWAL	HOST AKHIR	BROADCAST
1.	192.168.16.0	192.168.16.1	192.168.16.126	192.168.16.127
2.	192.168.16.128	192.168.16.129	192.168.16.254	192.168.16.255

Tahukah Kalian?

Selasa, 23 April 2013

SUBNETING IP ADDRES KELAS C

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